Calculate the empirical formula for nylon-6?
The most common form of nylon (nylon-6) is 63.68% carbon, 12.38% nitrogen, 9.8% hydrogen and 14.14% oxygen by mass. Calculate the empirical formula for nylon-6
Consider having 100 grams of this compound. The percentages of the elements given in the problem are numerically the same as the masses of these elements in our 100 g sample. We see a general principle that by assuming a 100 g sample, all percent signs can be changed to gram units.
C: 63.68 / 12.01 = 5.302 mol C
N: 12.38 / 14.01 = 0.8837 mol N
H: 9.8 / 1.008 = 9.72222 mol H
O: 14.14 / 16.00 = 0.88375 mol O
C5.302N0.8837H9.722O0.88375 –> preliminary empirical formula
Divide each subscript by the smallest, 0.8837,
resulting in C6 H11 N O
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